Thursday, May 5, 2022

Question 1: Given a list of employees, you need to filter all the employee whose age is greater than 20 and print the employee names.(Java 8 APIs only)

 Answer:
You can simply do it using the below statement.
List<String> employeeFilteredList = employeeList.stream() .filter(e->e.getAge()>20) .map(Employee::getName) .collect(Collectors.toList());

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import java.util.ArrayList; import java.util.List; import java.util.stream.Collectors; public class MaximumUsingStreamMain { public static void main(String args[]) { List<Employee> employeeList = createEmployeeList(); List<String> employeeFilteredList = employeeList.stream() .filter(e->e.getAge()>20) .map(Employee::getName) .collect(Collectors.toList()); employeeFilteredList.forEach((name)-> System.out.println(name)); } public static List<Employee> createEmployeeList() { List<Employee> employeeList=new ArrayList<>(); Employee e1=new Employee("John",21); Employee e2=new Employee("Martin",19); Employee e3=new Employee("Mary",31); Employee e4=new Employee("Stephan",18); Employee e5=new Employee("Gary",26); employeeList.add(e1); employeeList.add(e2); employeeList.add(e3); employeeList.add(e4); employeeList.add(e5); return employeeList; } }


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