One of the algo for this would be:
- Traverse the list and find the length of list
- After finding length, again traverse the list and locate n/2 element from head of linkedlist.
Time complexity=time for finding length of list + time for locating
middle element=o(n)+o(n) =o(n)
Space
complexity= o(1).
Efficient approach:
Above approach will take two traversal but we can find middle element in one traversal also using following algo
Use two pointer fastptr and slowptr and initialize both to head of linkedlist
- Move fastptr by two nodes and slowptr by one node in each iteration.
- When fastptr reaches end of nodes, the slowptr pointer will be pointing to middle element.
Lets create java program for it:
public class LinkedList{ private Node head; private static class Node { private int value; private Node next; Node(int value) { this.value = value; } } public void addToTheLast(Node node) { if (head == null) { head = node; } else { Node temp = head; while (temp.next != null) temp = temp.next; temp.next = node; } } public void printList() { Node temp = head; while (temp != null) { System.out.format("%d ", temp.value); temp = temp.next; } System.out.println(); } // This function will find middle element in linkedlist public Node findMiddleNode(Node head) { Node slowPointer, fastPointer; slowPointer = fastPointer = head; while(fastPointer !=null) { fastPointer = fastPointer.next; if(fastPointer != null && fastPointer.next != null) { slowPointer = slowPointer.next; fastPointer = fastPointer.next; } } return slowPointer; } public static void main(String[] args) { LinkedList list = new LinkedList(); // Creating a linked list Node head=new Node(5); list.addToTheLast(head); list.addToTheLast(new Node(6)); list.addToTheLast(new Node(7)); list.addToTheLast(new Node(1)); list.addToTheLast(new Node(2)); list.printList(); // finding middle element Node middle= list.findMiddleNode(head); System.out.println("Middle node will be: "+ middle.value); } }
Logically linked list can be represented as:
The middle element is represented in red color.
Run the above program, and you will get the following output:
5 6 7 1 2 Middle node is: 7
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